Problem Statement:
In, find the first value in JavaScript, we are given an array of numbers, we need to find the smallest number from the array that is divisible by 2 and 3 both.
Code to find the first value in JavaScript:
const numbers = [123, 675, 22, 645, 132, 23, 12, 18]
let newNumbers = []
for (let i = 0; i < numbers.length; i++) {
if(numbers[i]%2==0 && numbers[i]%3==0){
newNumbers.push(numbers[i])
}
}
console.log(Math.min(...newNumbers))Output:
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