Problem Statement:
In, find the first value in JavaScript, we are given an array of numbers, we need to find the smallest number from the array that is divisible by 2 and 3 both.
Code to find the first value in JavaScript:
const numbers = [123, 675, 22, 645, 132, 23, 12, 18]
let newNumbers = []
for (let i = 0; i < numbers.length; i++) {
if(numbers[i]%2==0 && numbers[i]%3==0){
newNumbers.push(numbers[i])
}
}
console.log(Math.min(...newNumbers))Output:
Also Read:
- Hyphenate Letters in Python
- Earthquake in Python | Easy Calculation
- Striped Rectangle in Python
- Perpendicular Words in Python
- Free shipping in Python
- Raj has ordered two electronic items Python | Assignment Expert
- Team Points in Python
- Ticket selling in Cricket Stadium using Python | Assignment Expert
- Split the sentence in Python
- String Slicing in JavaScript
- First and Last Digits in Python | Assignment Expert
- List Indexing in Python
- Date Format in Python | Assignment Expert
- New Year Countdown in Python
- Add Two Polynomials in Python
- Sum of even numbers in Python | Assignment Expert
- Evens and Odds in Python
- A Game of Letters in Python
- Sum of non-primes in Python
- Smallest Missing Number in Python
- String Rotation in Python
- Secret Message in Python
- Word Mix in Python
- Single Digit Number in Python
- Shift Numbers in Python | Assignment Expert
- Weekend in Python
- Shift Numbers in Python | Assignment Expert
- Temperature Conversion in Python
- Special Characters in Python
- Sum of Prime Numbers in the Input in Python
