## Problem Statement:

In this problem of the first perfect square in Python, we are given two numbers and we need to find the first perfect square that lies in the range of these two numbers.

## Code for first perfect square in Python:

```
import math
n1 = 26
n2 = 40
for i in range(n1, n2 + 1):
if math.ceil(math.sqrt(i)) == math.floor(math.sqrt(i)):
print(i)
break
else:
continue
print('No perfect square between ', n1, ' and ', n2)
```

## Output:

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